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(P)=81P^2-196
We move all terms to the left:
(P)-(81P^2-196)=0
We get rid of parentheses
-81P^2+P+196=0
a = -81; b = 1; c = +196;
Δ = b2-4ac
Δ = 12-4·(-81)·196
Δ = 63505
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{63505}}{2*-81}=\frac{-1-\sqrt{63505}}{-162} $$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{63505}}{2*-81}=\frac{-1+\sqrt{63505}}{-162} $
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